Version 4.1
SHEET 1 5164 2480
WIRE 2528 1344 2416 1344
WIRE 2416 1360 2416 1344
WIRE 2416 1456 2416 1440
WIRE 2608 1600 2368 1600
WIRE 2736 1600 2688 1600
WIRE 1936 1632 1920 1632
WIRE 2080 1632 1936 1632
WIRE 2368 1632 2368 1600
WIRE 2368 1632 2160 1632
WIRE 2528 1680 2528 1344
WIRE 2368 1696 2368 1632
WIRE 2448 1696 2368 1696
WIRE 2496 1696 2448 1696
WIRE 2736 1712 2736 1600
WIRE 2736 1712 2560 1712
WIRE 2800 1712 2736 1712
WIRE 1920 1728 1920 1632
WIRE 2416 1728 2144 1728
WIRE 2496 1728 2416 1728
WIRE 2528 1776 2528 1744
WIRE 2656 1776 2528 1776
WIRE 2656 1792 2656 1776
WIRE 2144 1840 2144 1728
WIRE 1920 1856 1920 1808
WIRE 1920 1968 1920 1936
WIRE 2064 1968 1920 1968
WIRE 2144 1968 2144 1920
WIRE 2144 1968 2064 1968
WIRE 2064 1984 2064 1968
FLAG 2656 1792 0
FLAG 2416 1456 0
FLAG 2800 1712 out
FLAG 2064 1984 0
FLAG 2448 1696 inv_ip
FLAG 2416 1728 non_inv_ip
FLAG 1936 1632 input
SYMBOL voltage 2416 1344 R0
SYMATTR InstName V5
SYMATTR Value 5
SYMBOL voltage 1920 1840 R0
SYMATTR InstName V1
SYMATTR Value 1V
SYMBOL voltage 2144 1824 R0
WINDOW 123 0 0 Left 0
WINDOW 39 0 0 Left 0
WINDOW 3 24 44 Left 2
SYMATTR Value 1V
SYMATTR InstName V2
SYMBOL OpAmps\\UniversalOpAmp2 2528 1712 R0
SYMATTR InstName U1
SYMATTR Value2 Avol=1Meg GBW=1Meg Slew=10Meg
SYMBOL res 2176 1616 R90
WINDOW 0 0 56 VBottom 2
WINDOW 3 32 56 VTop 2
SYMATTR InstName R1
SYMATTR Value 10k
SYMBOL res 2704 1584 R90
WINDOW 0 0 56 VBottom 2
WINDOW 3 32 56 VTop 2
SYMATTR InstName R2
SYMATTR Value 100k
SYMBOL voltage 1920 1712 R0
WINDOW 123 0 0 Left 0
WINDOW 39 0 0 Left 0
SYMATTR InstName V3
SYMATTR Value SINE(0 10m 1k)
TEXT 1256 920 Left 5 ;instructions
TEXT 1280 960 Left 2 ;click on run\nthen click on "non_inv_ip" to plot it.\nthen click on "inv_ip" to plot it\nthe two voltages are a maximum of 0.1mV apart, this is an indication that the circuit is working correctly\nthen click on the plot window then on plot settings / add plot pane\nthen click on "input" to plot it.\nthen click on "output" to plot it.\nnote that the AC magnitude of the output is 10 times the input, \nthe gain of 10 comes from R2/R1, that is 100k/10k = 10.\nthe opamps input terminals take no current, so R1 and R2 have to have the same current through them.\nso the ratio of their voltages is the same the ratio of their values.
TEXT 1232 608 Left 2 ;an opamp is optimised for applications where its ouput is at a voltage between the two supply rails, \nas opposed to a comparator which is optimised for applications where its output is either GND or Vcc\n \nan opamp has two inputs, which sense voltage, but take no current.\na "non inverting ip" typically labelled +\nand an "inverting ip" typically labelled -\nits output voltage is gain x ("non inverting ip" - "inverting ip")\nthe gain of the opamp is a big number, eg 100000.\na normal opamp circuit has the output voltage between its supply rails,\ndue to the high gain, this means that the two input pins are at almost the same voltage.
TEXT 1328 1880 Left 2 !.tran 10m
TEXT 1232 560 Left 5 ;description of an opamp
TEXT 2328 1824 Left 2 ;to find this component, \nclick on "component" in the toolbar,\nthen on "opamps", \nthen on "universalopamp2".