Version 4.1
SHEET 1 2336 680
WIRE -256 -192 -288 -192
WIRE -64 -192 -256 -192
WIRE 80 -192 16 -192
WIRE 432 -176 192 -176
WIRE 464 -176 432 -176
WIRE -288 -160 -288 -192
WIRE 80 -160 80 -192
WIRE 192 -160 192 -176
WIRE 464 -160 464 -176
WIRE 192 -64 192 -80
WIRE 320 -64 192 -64
WIRE 464 -64 464 -80
WIRE 464 -64 320 -64
WIRE -288 -48 -288 -80
WIRE 0 -48 -288 -48
WIRE 80 -48 80 -80
WIRE 80 -48 0 -48
WIRE 320 -32 320 -64
WIRE 0 -16 0 -48
FLAG 0 -16 0
FLAG -256 -192 50hz_250V
FLAG 320 -32 0
FLAG 432 -176 out
SYMBOL voltage -288 -176 R0
WINDOW 123 0 0 Left 0
WINDOW 39 0 0 Left 0
WINDOW 3 -56 107 Left 2
SYMATTR Value SINE(0 353 50 0 0)
SYMATTR InstName V1
SYMBOL ind2 64 -176 R0
SYMATTR InstName L1
SYMATTR Value 2H
SYMATTR Type ind
SYMATTR SpiceLine Rser=1m
SYMBOL ind2 176 -176 R0
SYMATTR InstName L2
SYMATTR Value 2H
SYMATTR Type ind
SYMATTR SpiceLine Rser=1m
SYMBOL res 448 -176 R0
SYMATTR InstName R1
SYMATTR Value 100R
SYMBOL res -80 -208 M90
WINDOW 0 -14 58 VBottom 2
WINDOW 3 32 56 VTop 2
SYMATTR InstName R_supply_current
SYMATTR Value 1m
TEXT 640 -368 Left 4 ;instructions
TEXT 640 -328 Left 2 ;click on run\nthen click on the "50hz_250V" net to plot its voltage.\nclick on the plot window,\nthen click on plot settings/add plot pane.\nthen click on the "out" net to plot its voltage.\nclick on the plot window,\nthen click on plot settings/add plot pane.\n then click on R1 to plot its current\nthen click on R_supply_current to plot its current
TEXT 64 -272 Left 2 !K1 L1 L2 1
TEXT 56 -312 Left 2 ;Transformer
TEXT -8 -360 Left 4 ;transformer circuit
TEXT -384 8 Left 2 !.tran 100m
TEXT 648 -48 Left 4 ;Description
TEXT 648 0 Left 2 ;This shows the concept of a transformer in its simplest form.\nthe transformer is defined by the Line "K1 L1 L2 1"\nthis couples L1 and L2 together making a transformer.\nthe coupling coefficient is 1 so no flux leakage.\nL1 and L2 have the same value so the turns ratio is 1.\n \nthe value of L1 and L2 are high enough that the transformer \nappears to take no current itself.... so with these values \nsupply current appears identical to load current.\nTry dropping the value of L1 and L2 to 0.2H, \nyou will see that load voltage and current remain the same,\nbut the supply current has risen as the transformer now \ntakes current itself.
RECTANGLE Normal 240 0 48 -320 2